x² + 2x + 1 = 0a² + b² = c²∫ 2x dx = x² + C3x + 7 = 22π r²sin²θ + cos²θ = 1⅓ + ¼ = 7/12y = mx + c2(3x − 4) + 5x√144 = 1215% of 200(x−3)(x+3)A = ½bhf′(x) = 6x + 2
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Problem: Solve for x: 3x + 5 = 20

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Subtract 5 from both sides: 3x = 20 - 5 = 15

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Divide both sides by 3: x = 15 ÷ 3 = 5

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Instant Explanations·
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